The ratio of incomes of Pankaj and Gauri is 3:5 and the ratio of their expenditures is 2:3. Who does save more?(You have to assume that no one takes any loan from anywhere)
Answer: B The ratio of income of Pankaj and gauri is 3:5. Ratio of their expenditures is 2:3 i.e 3:4.5 Had the ratio of expenditures been 3:5, ratio of savings also would have been 3:5, but since ratio of their expenditures is 3:4.5 only. Obviously savings of Gauri will be something more tha 5/3 of savings of Pankaj. Thus Gauri is the answer.
Q. No. 8:
The ratio of squares of first n natural numbers to square of sum of first n natural numbers is 17:325. The value of n is
Answer: B Sum of squares of first n natural numbers = n(n+1)(2n+1)/6. Squares of sum of first n natural numbers = (n(n+1)/2)*(n(n+1)/2) Now the ratio is 17:325 Thus , by solving we get n= 25.
Q. No. 9:
GPL and KTC quote for a tender. On the tender opening day, GPL realizes that their quotations are in the ratio 7:4 and hence decreases its price during negotiations to make it Rs 1Lakh lower than KTC's quoted price. KTC realizes that the final quotes of the two were in the ratio 3:4. What was the price at which GPL won the bid?
Answer: C GPL initially quoted Rs 7x lakh. KTC quoted 4x lakh. GPL's final quote = (4x-1) Lakh Thus, (4x-1)/4x = 3/4 => x= 1. GPL's bid winning price = Rs 3 Lakh So IBM wins the bid at 4x-1 = Rs 3 lakh.
Q. No. 10:
The total surface area of a solid iron cube and a solid aluminium cuboid are the same. The length, breadth and height of the cuboid are in the ratio 1:2:4. Both are melted together in a vessel. What is the ratio of iron and aluminium in the resultant mixture?
Answer: A 6a2= 2(lb+bh+hl) l:b:h = 1:2:4. Therefore, b=2l, h= 4l Hence, 6a2 = 2[2l2 +8l2 +4l2 ] 6a2= 28l2 a3= (14/3)3/2l3 Ratio of the volumes of the cube and cuboid => a3: lbh =(14/3)3/2:8
Q. No. 11:
In a house, there are dogs, cats and parrot in the ratio 3:7:5. If the number of cats was more than the number of dogs by a multiple of both 9 and 7, what is the minimum of pets in the house?
Answer: A If three kinds of pets are taken be 3k, 7k and 5k respectively, then 7k-3k = 63p (where p is any positive integer). As the number is a multiple of both 9 and 7, it has to be multiple of 63. => k= 63p/4. Minimum value of p for which k is a natural number is 4. Thus, k= 63. Hence, the number of pets = 15k = 945
Q. No. 12:
By mistake, in stead of dividing Rs 177 among three persons P, Q and R in the ratio 1/2:1/3:1/4, it was divided in the ratio 2:3:4. Who gains the most and how much?
Answer: C ratio 1/2:1/3:1/4 is equivalent to 6:4:3 So, in case, P,Q and R would have got Rs 54, Rs 36 and Rs 27 respectively. But actually the money was divided in the ratio 2:3:4 and shares of P,Q and R in this case was 26, 39 and 52 respectively.